这篇真的很好,我就是靠这个真正明白的。
例题:
- 缩点模版:
代码:1
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using namespace std;
int n,m;
const int N = 100005;
struct Edge
{
    int v,next;
}e[N*2],e1[N*2];
int front[N],cnt = 0,val[N],co[N],stk[N],dfn[N],low[N],f[N],vl[N];
bool instk[N];
int cnt1 = 0, front1[N],tot = 0;
int tp = 0, t = 0;
void AddEdge(int u,int v)
{
    e[++cnt].v = v;
    e[cnt].next = front[u];
    front[u] = cnt;
}
void AddEdge1(int u,int v)
{
    e1[++cnt1].v = v;
    e1[cnt1].next = front1[u];
    front1[u] = cnt1;
}
void tarjan(int now)
{
    dfn[now] = low[now] = ++t;
    instk[now] = true;
    stk[++tp] = now;
    for (int i = front[now]; i; i = e[i].next)
    {
        int xx = e[i].v;
        if(!dfn[xx])
        {
            tarjan(xx);
            low[now] = min(low[now],low[xx]);
        }
        else if (instk[xx])
        {
            low[now] = min(low[now],dfn[xx]);
        }
    }
    if(dfn[now] == low[now])
    {
        tot++;
        vl[tot] = 0;
        while(stk[tp+1] != now)
        {
            int xx = stk[tp];
            vl[tot] += val[xx];
            tp--;
            instk[xx] = false;
            co[xx] = tot;
        }
    }
}
void search(int x)
{
    if(f[x]) return;
    f[x] = vl[x];
    int maxs = 0;
    for (int i = front1[x]; i; i = e1[i].next)
    {
        int xx = e1[i].v;
        if(!f[xx]) search(xx);
        maxs = max(maxs, f[xx]);
    }
    f[x] += maxs;
}
int main()
{
    scanf("%d%d",&n,&m);
    for (int i = 1; i <= n; i++) scanf("%d",&val[i]);
    for (int i = 1; i <= m; i++)
    {
        int a,b;
        scanf("%d%d",&a,&b);
        AddEdge(a,b);
    }
    for (int i = 1; i <= n; i++)
    {
        if (!dfn[i]) tarjan(i);
    }
    for (int k = 1; k <= n; k++)
    {
        for (int i = front[k]; i; i = e[i].next)
        {
            int xx = e[i].v;
            if(co[xx] != co[k]) AddEdge1(co[k],co[xx]);
        }
    }
//	cout<<tot<<endl;
    int cur,res = 0;
    memset(f,0,sizeof f);
    for (int k = 1; k <= tot; k++)
    {
        //cout<< vl[k] <<endl;
        //cout<<vl[k]<<endl;
        if (!f[k]) search(k);
    //	cout<< k <<" "<<f[k]<<endl;
        res = max(res, f[k]);
    }
    printf("%d\n", res);
    return 0;
}
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